What is the integral of 9(sec(x))^2 ?

The integral of 9(sec(x))^2 is 9tan(x)+C

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integral of 9(sec(x))^2

\int 9 (sec (x))^{2} d x

9 tan (x) + C

Solution steps

\int 9 (sec (x))^{2} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 9 \cdot \int (sec (x))^{2} d x

Simplify

= 9 \cdot \int sec^{2} (x) d x

Use the common integral:

\int sec^{2} (x) d x = tan (x)

= 9 tan (x)

Add a constant to the solution

= 9 tan (x) + C

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