What is the derivative of 1/((3x+1)) ?

The derivative of 1/((3x+1)) is -3/((3x+1)^2)

What is the first derivative of 1/((3x+1)) ?

The first derivative of 1/((3x+1)) is -3/((3x+1)^2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

\frac{1}{( 3 x + 1 )}

- \frac{3}{( 3 x + 1 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{1}{3 x + 1})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{d}{d x} ((3 x + 1)^{- 1})

Apply the chain rule:

- \frac{1}{( 3 x + 1 ) ^{2}} \frac{d}{d x} (3 x + 1)

= - \frac{1}{( 3 x + 1 ) ^{2}} \frac{d}{d x} (3 x + 1)

\frac{d}{d x} (3 x + 1) = 3

= - \frac{1}{( 3 x + 1 ) ^{2}} \cdot 3

Simplify

- \frac{1}{( 3 x + 1 ) ^{2}} \cdot 3 : - \frac{3}{( 3 x + 1 ) ^{2}}

= - \frac{3}{( 3 x + 1 ) ^{2}}

y = sin (x), y = cos (x)

(e^{, at})

\int x + 4 d x

\int p^{2} ln (p) d p

x \to 0 lim (x^{2} - 2 x)

What is the derivative of 1/((3x+1)) ?
The derivative of 1/((3x+1)) is -3/((3x+1)^2)
What is the first derivative of 1/((3x+1)) ?
The first derivative of 1/((3x+1)) is -3/((3x+1)^2)