What is the tangent of f(x)= 1/x ,\at x=0.501 ?

The tangent of f(x)= 1/x ,\at x=0.501 is y=-3.98404…x+3.99201…

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tangent of f(x)= 1/x ,\at x=0.501

tangent of

f (x) = \frac{1}{x}, at x = 0.501

y = - 3.98404 \dots x + 3.99201 \dots

Solution steps

Find the tangent point:

(0.501, \frac{1}{0.501})

Find the slope of

f (x) = \frac{1}{x} : \frac{df ( x )}{d x} = - \frac{1}{x ^{2}}

Compute the slope of

f (x) = \frac{1}{x}

x = 0.501 : m = - 3.98404 \dots

Find the line with slope m=

- 3.98404 \dots

and passing through

(0.501, \frac{1}{0.501}) : y = - 3.98404 \dots x + 3.99201 \dots

y = - 3.98404 \dots x + 3.99201 \dots

\int 4 x + 4 sin (x) d x

\frac{d}{d x} (\frac{3 x}{x ^{2} + 3})

\frac{d}{d x} (6 arcsin (x^{4}))

\frac{d y}{d x} = x + 5 y, y (0) = 3

x \to 0 lim (cos^{\frac{3}{x ^{2}}} (2 x))

What is the tangent of f(x)= 1/x ,\at x=0.501 ?
The tangent of f(x)= 1/x ,\at x=0.501 is y=-3.98404…x+3.99201…