What is (\partial)/(\partial x)(2x^{0.5}+y) ?

The answer to (\partial)/(\partial x)(2x^{0.5}+y) is 1/(x^{1/2)}

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(\partial)/(\partial x)(2x^{0.5}+y)

\frac{\partial}{\partial x} (2 x^{0.5} + y)

\frac{1}{x ^{\frac{1}{2}}}

Solution steps

\frac{\partial}{\partial x} (2 x^{0.5} + y)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (2 x^{0.5}) + \frac{\partial}{\partial x} (y)

\frac{\partial}{\partial x} (2 x^{0.5}) = \frac{1}{x ^{0.5}}

\frac{\partial}{\partial x} (y) = 0

= \frac{1}{x ^{0.5}} + 0

Simplify

= \frac{1}{x ^{\frac{1}{2}}}

(x + 1) \frac{d y}{d x} + x y = ln (x)

f (x) = 8 x e^{x} csc (x)

\frac{d}{d x} (7 x)

\int_{6}^{8} \frac{40}{( x - 6 ) ^{3}} d x

\int \frac{1}{8 x - 1} d x

What is (\partial)/(\partial x)(2x^{0.5}+y) ?
The answer to (\partial)/(\partial x)(2x^{0.5}+y) is 1/(x^{1/2)}