What is the integral of (6x)/(x^2) ?

The integral of (6x)/(x^2) is 6ln|x|+C

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integral of (6x)/(x^2)

\int \frac{6 x}{x ^{2}} d x

6 ln ∣ x ∣ + C

Solution steps

\int \frac{6 x}{x ^{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 6 \cdot \int \frac{x}{x ^{2}} d x

Cancel the common factor:

x

= 6 \cdot \int \frac{1}{x} d x

Use the common integral:

\int \frac{1}{x} d x = ln (∣ x ∣)

= 6 ln ∣ x ∣

Add a constant to the solution

= 6 ln ∣ x ∣ + C

x + \frac{3}{x}

\int 24 tan^{3} (x) d x

y = 3 x, x = 1

y^{^{'}} - 3 y = e^{2 x}