What is the derivative of 1/4 x^4-2x^2 ?

The derivative of 1/4 x^4-2x^2 is x^3-4x

What is the first derivative of 1/4 x^4-2x^2 ?

The first derivative of 1/4 x^4-2x^2 is x^3-4x

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\frac{d}{d x} (\frac{1}{4} x^{4} - 2 x^{2})

x^{3} - 4 x

Solution steps

\frac{d}{d x} (\frac{1}{4} x^{4} - 2 x^{2})

Simplify

\frac{1}{4} x^{4} - 2 x^{2} : \frac{x ^{4}}{4} - 2 x^{2}

= \frac{d}{d x} (\frac{x ^{4}}{4} - 2 x^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{x ^{4}}{4}) - \frac{d}{d x} (2 x^{2})

\frac{d}{d x} (\frac{x ^{4}}{4}) = x^{3}

\frac{d}{d x} (2 x^{2}) = 4 x

= x^{3} - 4 x

d x + e^{8 x} d y = 0

\frac{\partial}{\partial v} (sin (v) cos (u))

\int \frac{sin ( 2 x )}{28 + cos ^{2} ( x )} d x

y^{^{'}} - y = 1

What is the derivative of 1/4 x^4-2x^2 ?
The derivative of 1/4 x^4-2x^2 is x^3-4x
What is the first derivative of 1/4 x^4-2x^2 ?
The first derivative of 1/4 x^4-2x^2 is x^3-4x