What is the integral of e^{-2x+1} ?

The integral of e^{-2x+1} is -1/2 e^{-2x+1}+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of e^{-2x+1}

\int e^{- 2 x + 1} d x

- \frac{1}{2} e^{- 2 x + 1} + C

Solution steps

\int e^{- 2 x + 1} d x

Apply u-substitution

: \int - \frac{1}{2} e^{u} d u

= \int - \frac{1}{2} e^{u} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \frac{1}{2} \cdot \int e^{u} d u

Use the common integral:

\int e^{u} d u = e^{u}

= - \frac{1}{2} e^{u}

Substitute back

u = - 2 x + 1

= - \frac{1}{2} e^{- 2 x + 1}

Add a constant to the solution

= - \frac{1}{2} e^{- 2 x + 1} + C

\frac{\partial}{\partial x} (- 3 x y (- 9 - x - y))

\int 3 e^{- x} d x

n = 1 \sum \infty n^{2} \cdot e^{- n^{3}}

\int \frac{3 x ^{2}}{( x ^{3} + 1 ) ^{2}} d x

x \to 0 + lim (x^{4} ln (x))

What is the integral of e^{-2x+1} ?
The integral of e^{-2x+1} is -1/2 e^{-2x+1}+C