What is the derivative of 2cos(2y) ?

The derivative of 2cos(2y) is -4sin(2y)

What is the first derivative of 2cos(2y) ?

The first derivative of 2cos(2y) is -4sin(2y)

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derivative of

2 cos (2 y)

- 4 sin (2 y)

Solution steps

\frac{d}{d y} (2 cos (2 y))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d y} (cos (2 y))

Apply the chain rule:

- sin (2 y) \frac{d}{d y} (2 y)

= - sin (2 y) \frac{d}{d y} (2 y)

\frac{d}{d y} (2 y) = 2

= 2 (- sin (2 y) \cdot 2)

Simplify

= - 4 sin (2 y)

\int_{0}^{2} 4 x^{2} d x

\frac{\partial}{\partial x} (ln (1 - 2 x))

\int_{1}^{2} \frac{1}{2 - x} d x

\frac{e ^{2 x + 1}}{2 x + 5}

\int_{0}^{2} x e^{- 4 x} d x

What is the derivative of 2cos(2y) ?
The derivative of 2cos(2y) is -4sin(2y)
What is the first derivative of 2cos(2y) ?
The first derivative of 2cos(2y) is -4sin(2y)