What is the integral of (1/(4\sqrt[8]{x^2)}) ?

The integral of (1/(4\sqrt[8]{x^2)}) is 1/3 x^{3/4}+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of (1/(4\sqrt[8]{x^2)})

\frac{1}{3} x^{\frac{3}{4}} + C

Solution steps

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

assuming

x \geq 0

Apply the Power Rule

: \frac{4}{3} x^{\frac{3}{4}}

= \frac{1}{4} \cdot \frac{4}{3} x^{\frac{3}{4}}

Simplify

\frac{1}{4} \cdot \frac{4}{3} x^{\frac{3}{4}} : \frac{1}{3} x^{\frac{3}{4}}

= \frac{1}{3} x^{\frac{3}{4}}

Add a constant to the solution

= \frac{1}{3} x^{\frac{3}{4}} + C

f (x) = (3 x + 4) (5 - x^{2}) (4 + x^{2})

x \to \infty lim (e^{x} + 3)

\int_{0}^{\infty} e^{- \frac{x}{4}} d x

x \to 0 lim ((1 + x)^{\frac{2}{x}})

What is the integral of (1/(4\sqrt[8]{x^2)}) ?
The integral of (1/(4\sqrt[8]{x^2)}) is 1/3 x^{3/4}+C