What is laplacetransform sin(5t) ?

The answer to laplacetransform sin(5t) is 5/(s^2+25)

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laplacetransform sin(5t)

laplace transform

sin (5 t)

\frac{5}{s ^{2} + 25}

Solution steps

L {sin (5 t)}

Use Laplace Transform table:

L {sin (a t)} = \frac{a}{s ^{2} + a ^{2}}

L {sin (5 t)} = \frac{5}{s ^{2} + 5 ^{2}}

= \frac{5}{s ^{2} + 5 ^{2}}

= \frac{5}{s ^{2} + 25}

\frac{\partial}{\partial x} (- 3 x y (- 3 - x - y))

\frac{d y}{d x} = \frac{( x ^{2} + y )}{x ^{3}}

f (x) = ln (x + 2)

\int_{8}^{9} \frac{1}{x ^{2} - 1} d x

y = 9 - x^{2}, 0 \leq x \leq 2

What is laplacetransform sin(5t) ?
The answer to laplacetransform sin(5t) is 5/(s^2+25)