What is the solution for y^'=(e^t)/(2y) ?

The solution for y^'=(e^t)/(2y) is y=sqrt(e^t+c_{1)},y=-sqrt(e^t+c_{1)}

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y^'=(e^t)/(2y)

y^{^{'}} = \frac{e ^{t}}{2 y}

y = e^{t} + c_{1}, y = - e^{t} + c_{1}

Solution steps

y^{'} (t) = \frac{e ^{t}}{2 y}

Solve separable ODE:

y = e^{t} + c_{1}, y = - e^{t} + c_{1}

y = e^{t} + c_{1}, y = - e^{t} + c_{1}

\int (sin^{4} (x) cos (x)) d x

f (x) = x^{2} - 4, (- 5, 21)

n = 1 \sum \infty \frac{6}{n}

\frac{d}{d x} (2 + 6 x)

\frac{d}{d y} (y^{y})

What is the solution for y^'=(e^t)/(2y) ?
The solution for y^'=(e^t)/(2y) is y=sqrt(e^t+c_{1)},y=-sqrt(e^t+c_{1)}