What is the integral of-510x^2+3414x+1998 ?

The integral of-510x^2+3414x+1998 is -170x^3+1707x^2+1998x+C

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integral of-510x^2+3414x+1998

\int - 510 x^{2} + 3414 x + 1998 d x

- 170 x^{3} + 1707 x^{2} + 1998 x + C

Solution steps

\int - 510 x^{2} + 3414 x + 1998 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int 510 x^{2} d x + \int 3414 x d x + \int 1998 d x

\int 510 x^{2} d x = 170 x^{3}

\int 3414 x d x = 1707 x^{2}

\int 1998 d x = 1998 x

= - 170 x^{3} + 1707 x^{2} + 1998 x

Add a constant to the solution

= - 170 x^{3} + 1707 x^{2} + 1998 x + C

x \to \infty lim (\frac{225 x ^{2} + 7 x - 23}{15 x})

\int cos (x) x d x

f (x) = (9 - x^{3})^{- 2}

10 y^{^{''}} + 2 y^{^{'}} + 5 y = 0

\frac{d y}{d x} = \frac{4 y}{x}

What is the integral of-510x^2+3414x+1998 ?
The integral of-510x^2+3414x+1998 is -170x^3+1707x^2+1998x+C