What is area 5cos(2x),5-5cos(2x),0, pi/2 ?

The answer to area 5cos(2x),5-5cos(2x),0, pi/2 is 5sqrt(3)+(5pi)/6

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area 5cos(2x),5-5cos(2x),0, pi/2

area

5 cos (2 x), 5 - 5 cos (2 x), 0, \frac{π}{2}

53 + \frac{5 π}{6}

Decimal Notation

11.27824 \dots

Solution steps

Apply the area formula:

\int_{0}^{\frac{π}{2}} ∣ 5 cos (2 x) - (5 - 5 cos (2 x)) ∣ d x

Solve

\int_{0}^{\frac{π}{2}} ∣ 5 cos (2 x) - (5 - 5 cos (2 x)) ∣ d x : 53 + \frac{5 π}{6}

The area is:

= 53 + \frac{5 π}{6}

\int \frac{20 x ^{3}}{4 + 5 x ^{4}} d x

y^{^{''}} + 4 y = t \cdot sin (2 t)

2 + 5 arctan (\frac{x}{2})

\frac{1}{( x + 6 ) ^{2}}

x y^{^{'}} + y = yy

What is area 5cos(2x),5-5cos(2x),0, pi/2 ?
The answer to area 5cos(2x),5-5cos(2x),0, pi/2 is 5sqrt(3)+(5pi)/6