What is the derivative of 0.006x^3+0.02x^2+0.5x ?

The derivative of 0.006x^3+0.02x^2+0.5x is 0.018x^2+0.04x+0.5

What is the first derivative of 0.006x^3+0.02x^2+0.5x ?

The first derivative of 0.006x^3+0.02x^2+0.5x is 0.018x^2+0.04x+0.5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (0.006 x^{3} + 0.02 x^{2} + 0.5 x)

0.018 x^{2} + 0.04 x + 0.5

Solution steps

\frac{d}{d x} (0.006 x^{3} + 0.02 x^{2} + 0.5 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (0.006 x^{3}) + \frac{d}{d x} (0.02 x^{2}) + \frac{d}{d x} (0.5 x)

\frac{d}{d x} (0.006 x^{3}) = 0.018 x^{2}

\frac{d}{d x} (0.02 x^{2}) = 0.04 x

\frac{d}{d x} (0.5 x) = 0.5

= 0.018 x^{2} + 0.04 x + 0.5

\frac{d}{d y} (y cos (x) y)

3 x^{2} - 9

y^{^{'}} = \frac{e ^{x}}{y ^{2}}

\frac{\partial}{\partial x} (2 y + z)

\int \frac{x}{x + 4} d x

What is the derivative of 0.006x^3+0.02x^2+0.5x ?
The derivative of 0.006x^3+0.02x^2+0.5x is 0.018x^2+0.04x+0.5
What is the first derivative of 0.006x^3+0.02x^2+0.5x ?
The first derivative of 0.006x^3+0.02x^2+0.5x is 0.018x^2+0.04x+0.5