What is the s(t)=(t^2+40t)/5 ?

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s(t)=(t^2+40t)/5

s (t) = \frac{t ^{2} + 40 t}{5}

Domain : - \infty < t < \infty

Range : f (t) \geq - 80

X Intercepts : (0, 0), (- 40, 0), Y Intercepts : (0, 0)

Vertex : Minimum (- 20, - 80)

Inverse : \frac{- 40 + 1600 + 20 t}{2}, \frac{- 40 - 1600 + 20 t}{2}

Interval Notation

Domain : (- \infty, \infty)

Range : [- 80, \infty)

Solution steps

Domain of

\frac{t ^{2} + 40 t}{5} : - \infty < t < \infty

Range of

\frac{t ^{2} + 40 t}{5} : f (t) \geq - 80

Axis interception points of

\frac{t ^{2} + 40 t}{5} :

X Intercepts

: (0, 0), (- 40, 0),

Y Intercepts

: (0, 0)

Vertex of

\frac{t ^{2} + 40 t}{5} :

Minimum

(- 20, - 80)

Inverse of

\frac{t ^{2} + 40 t}{5} : \frac{- 40 + 1600 + 20 t}{2}, \frac{- 40 - 1600 + 20 t}{2}

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