What is the limit as x approaches 0 of 2^{1/x} ?

The limit as x approaches 0 of 2^{1/x} is diverges

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limit as x approaches 0 of 2^{1/x}

x \to 0 lim (2^{\frac{1}{x}})

diverges

Solution steps

x \to 0 lim (2^{\frac{1}{x}})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 0 + lim (2^{\frac{1}{x}}) = \infty

x \to 0 - lim (2^{\frac{1}{x}}) = 0

= diverges

\int - \frac{1}{x + 8} + \frac{9}{x - 4} d x

f (x) = - \frac{1}{x ^{2}}

\frac{d}{d x} (x^{- 5 c o s (x)})

x \to 1 lim (4 x^{2} + 2 x + 5)

\frac{d}{d x} (- 3 ln (x))

What is the limit as x approaches 0 of 2^{1/x} ?
The limit as x approaches 0 of 2^{1/x} is diverges