What is the solution for 2y(dy)/(dx)+2=y^2+2x ?

The solution for 2y(dy)/(dx)+2=y^2+2x is y=sqrt(-2x+c_{1)e^x},y=-sqrt(-2x+c_{1)e^x}

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2y(dy)/(dx)+2=y^2+2x

2 y \frac{d y}{d x} + 2 = y^{2} + 2 x

y = - 2 x + c_{1} e^{x}, y = - - 2 x + c_{1} e^{x}

Solution steps

2 y \frac{d y}{d x} + 2 = y^{2} + 2 x

Solve Bernoulli ODE:

y = - 2 x + c_{1} e^{x}, y = - - 2 x + c_{1} e^{x}

y = - 2 x + c_{1} e^{x}, y = - - 2 x + c_{1} e^{x}

\frac{d y}{d x} = \frac{x}{y}

y^{^{''}} + 8 y^{^{'}} + 20 y = 40, y (0) = 0, y^{^{'}} (0) = 0

\int csc (t) d t

\frac{d ^{2} y}{d x ^{2}} - 6 \frac{d y}{d x} + 9 y = x e^{x}

f (x) = 2 x^{3} - 8 x, (- 2, 0)

What is the solution for 2y(dy)/(dx)+2=y^2+2x ?
The solution for 2y(dy)/(dx)+2=y^2+2x is y=sqrt(-2x+c_{1)e^x},y=-sqrt(-2x+c_{1)e^x}