What is (\partial)/(\partial x)(2sin(4x)) ?

The answer to (\partial)/(\partial x)(2sin(4x)) is 8cos(4x)

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(\partial)/(\partial x)(2sin(4x))

\frac{\partial}{\partial x} (2 sin (4 x))

8 cos (4 x)

Solution steps

\frac{\partial}{\partial x} (2 sin (4 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{\partial}{\partial x} (sin (4 x))

Apply the chain rule:

cos (4 x) \frac{\partial}{\partial x} (4 x)

= cos (4 x) \frac{\partial}{\partial x} (4 x)

\frac{\partial}{\partial x} (4 x) = 4

= 2 cos (4 x) \cdot 4

Simplify

= 8 cos (4 x)

\frac{d y}{d x} = (x)

x \to 0 lim (+ (x^{s i n (x)}))

y^{^{''}} + 18 y^{^{'}} + 82 y = 0

\int_{0}^{2} 2 π (y + 1) (1) d y

f (x) = x^{\frac{6}{7}}

What is (\partial)/(\partial x)(2sin(4x)) ?
The answer to (\partial)/(\partial x)(2sin(4x)) is 8cos(4x)