What is the derivative of-x^2+x ?

The derivative of-x^2+x is -2x+1

What is the first derivative of-x^2+x ?

The first derivative of-x^2+x is -2x+1

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\frac{d}{d x} (- x^{2} + x)

- 2 x + 1

Solution steps

\frac{d}{d x} (- x^{2} + x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (x^{2}) + \frac{d x}{d x}

\frac{d}{d x} (x^{2}) = 2 x

\frac{d x}{d x} = 1

= - 2 x + 1

f (t) = t^{2} + 4 t

\int \frac{1}{( 1 + y ) ^{2}} d y

\int_{- 1}^{1} 5^{x} d x

x \to 0 - lim (\frac{1}{x ^{2}})

\int \frac{1}{( 196 - x ^{2} ) ^{\frac{3}{2}}} d x