What is the derivative of (x+pi^2) ?

The derivative of (x+pi^2) is 2(x+pi)

What is the first derivative of (x+pi^2) ?

The first derivative of (x+pi^2) is 2(x+pi)

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\frac{d}{d x} ((x + π)^{2})

2 (x + π)

Solution steps

\frac{d}{d x} ((x + π)^{2})

Apply the chain rule:

2 (x + π) \frac{d}{d x} (x + π)

= 2 (x + π) \frac{d}{d x} (x + π)

\frac{d}{d x} (x + π) = 1

= 2 (x + π) \cdot 1

Simplify

= 2 (x + π)

\frac{d}{d x} (x^{3} ln (1 + x^{2}))

\int_{0}^{3} \frac{x - 2}{x ^{2} - 3 x - 4} d x

x y^{6} y^{^{'}} = x^{7} + y^{7}

\int_{1}^{4} \frac{5}{x ^{2} + 4 x + 4} d x

\frac{\partial}{\partial x} (4 x^{3} y^{2} + 1)

What is the derivative of (x+pi^2) ?
The derivative of (x+pi^2) is 2(x+pi)
What is the first derivative of (x+pi^2) ?
The first derivative of (x+pi^2) is 2(x+pi)