What is the sum from n=0 to infinity of 1/(n+13) ?

The sum from n=0 to infinity of 1/(n+13) is diverges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sum from n=0 to infinity of 1/(n+13)

n = 0 \sum \infty \frac{1}{n + 13}

diverges

Solution steps

n = 0 \sum \infty \frac{1}{n + 13}

Apply Series Integral Test:

diverges

= diverges

\int \frac{y}{( y ^{2} - 4 ) ^{\frac{2}{5}}} d y

f (x) = 12 x - x^{3}

\int - cos (n x) d x

\frac{d y}{d x} = \frac{x ^{3} + y ^{3}}{x y ^{2}}

What is the sum from n=0 to infinity of 1/(n+13) ?
The sum from n=0 to infinity of 1/(n+13) is diverges