What is the derivative of ln(4x-5) ?

The derivative of ln(4x-5) is 4/(4x-5)

What is the first derivative of ln(4x-5) ?

The first derivative of ln(4x-5) is 4/(4x-5)

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\frac{d}{d x} (ln (4 x - 5))

\frac{4}{4 x - 5}

Solution steps

\frac{d}{d x} (ln (4 x - 5))

Apply the chain rule:

\frac{1}{4 x - 5} \frac{d}{d x} (4 x - 5)

= \frac{1}{4 x - 5} \frac{d}{d x} (4 x - 5)

\frac{d}{d x} (4 x - 5) = 4

= \frac{1}{4 x - 5} \cdot 4

Simplify

\frac{1}{4 x - 5} \cdot 4 : \frac{4}{4 x - 5}

= \frac{4}{4 x - 5}

\frac{1}{1 - x - x ^{2}}

t - 2

f (x) = x^{2} + 4, at x = - 1

\int \frac{( x ^{2} - x + 18 )}{x ^{3} + 3 x} d x

\int (3 x^{4}) d x

What is the derivative of ln(4x-5) ?
The derivative of ln(4x-5) is 4/(4x-5)
What is the first derivative of ln(4x-5) ?
The first derivative of ln(4x-5) is 4/(4x-5)