What is area x=1,x=3,y=x^3-8,y=0 ?

The answer to area x=1,x=3,y=x^3-8,y=0 is 25/2

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area x=1,x=3,y=x^3-8,y=0

area

x = 1, x = 3, y = x^{3} - 8, y = 0

\frac{25}{2}

Solution steps

Apply the area formula:

\int_{1}^{3} x^{3} - 8 d x

Solve

\int_{1}^{3} x^{3} - 8 d x : \frac{25}{2}

The area is:

= \frac{25}{2}

2 (t - 3)^{2} + 15 (t - 3) + 26

\frac{d}{d x} (\frac{8 ( 4 ^{x} )}{x ^{4}})

\int_{0}^{\frac{1}{3}} \frac{5}{1 + 9 x ^{2}} d x

\frac{d}{d x} (\frac{1}{2} ln (\frac{x}{2}))

\frac{d}{d x} (x^{\frac{2}{3}} (x - 4))

What is area x=1,x=3,y=x^3-8,y=0 ?
The answer to area x=1,x=3,y=x^3-8,y=0 is 25/2