What is the derivative of 3xe^x-cos(x) ?

The derivative of 3xe^x-cos(x) is 3(e^x+e^xx)+sin(x)

What is the first derivative of 3xe^x-cos(x) ?

The first derivative of 3xe^x-cos(x) is 3(e^x+e^xx)+sin(x)

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\frac{d}{d x} (3 x e^{x} - cos (x))

3 (e^{x} + e^{x} x) + sin (x)

Solution steps

\frac{d}{d x} (3 x e^{x} - cos (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x e^{x}) - \frac{d}{d x} (cos (x))

\frac{d}{d x} (3 x e^{x}) = 3 (e^{x} + e^{x} x)

\frac{d}{d x} (cos (x)) = - sin (x)

= 3 (e^{x} + e^{x} x) - (- sin (x))

Simplify

= 3 (e^{x} + e^{x} x) + sin (x)

f (t) = 5 - t

(ln (1 + 2 x))^{^{'}}

\frac{\partial}{\partial x} (x^{2} + 3 y^{2})

\int \frac{1}{( 36 - x ^{2} ) ^{\frac{3}{2}}} d x

(4 t^{5} - 6 t)^{8}

What is the derivative of 3xe^x-cos(x) ?
The derivative of 3xe^x-cos(x) is 3(e^x+e^xx)+sin(x)
What is the first derivative of 3xe^x-cos(x) ?
The first derivative of 3xe^x-cos(x) is 3(e^x+e^xx)+sin(x)