What is the derivative of sqrt(x)-3e^x ?

The derivative of sqrt(x)-3e^x is 1/(2sqrt(x))-3e^x

What is the first derivative of sqrt(x)-3e^x ?

The first derivative of sqrt(x)-3e^x is 1/(2sqrt(x))-3e^x

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\frac{d}{d x} (x - 3 e^{x})

\frac{1}{2 x} - 3 e^{x}

Solution steps

\frac{d}{d x} (x - 3 e^{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x) - \frac{d}{d x} (3 e^{x})

\frac{d}{d x} (x) = \frac{1}{2 x}

\frac{d}{d x} (3 e^{x}) = 3 e^{x}

= \frac{1}{2 x} - 3 e^{x}

\int 2 sin (x) cos (x) d x

\frac{\partial}{\partial x} (ln (x^{2} + 3))

x \to 2 lim (\frac{2 x - 4}{x - 2})

(3 x^{2} + y - 4) - (2 y - x) \frac{d y}{d x} = 0

\int 3 ln (x) d x

What is the derivative of sqrt(x)-3e^x ?
The derivative of sqrt(x)-3e^x is 1/(2sqrt(x))-3e^x
What is the first derivative of sqrt(x)-3e^x ?
The first derivative of sqrt(x)-3e^x is 1/(2sqrt(x))-3e^x