What is the derivative of sqrt(2x+2) ?

The derivative of sqrt(2x+2) is 1/(sqrt(2x+2))

What is the first derivative of sqrt(2x+2) ?

The first derivative of sqrt(2x+2) is 1/(sqrt(2x+2))

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\frac{d}{d x} (2 x + 2)

\frac{1}{2 x + 2}

Solution steps

\frac{d}{d x} (2 x + 2)

Apply the chain rule:

\frac{1}{2 2 x + 2} \frac{d}{d x} (2 x + 2)

= \frac{1}{2 2 x + 2} \frac{d}{d x} (2 x + 2)

\frac{d}{d x} (2 x + 2) = 2

= \frac{1}{2 2 x + 2} \cdot 2

Simplify

\frac{1}{2 2 x + 2} \cdot 2 : \frac{1}{2 x + 2}

= \frac{1}{2 x + 2}

\int \frac{x}{e ^{- 2 x}} d x

\int \frac{1}{u ^{2} + 2} d u

\int_{0}^{1} e^{s} sin (t - s) d s

f (x) = x^{3} - 9 x, at x = (- 3)

f (x) = 2 x - \frac{1}{x}, at x = 0.5

What is the derivative of sqrt(2x+2) ?
The derivative of sqrt(2x+2) is 1/(sqrt(2x+2))
What is the first derivative of sqrt(2x+2) ?
The first derivative of sqrt(2x+2) is 1/(sqrt(2x+2))