What is the derivative of 2sin(x-cos(2x)) ?

The derivative of 2sin(x-cos(2x)) is 2cos(x)+2sin(2x)

What is the first derivative of 2sin(x-cos(2x)) ?

The first derivative of 2sin(x-cos(2x)) is 2cos(x)+2sin(2x)

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\frac{d}{d x} (2 sin (x) - cos (2 x))

2 cos (x) + 2 sin (2 x)

Solution steps

\frac{d}{d x} (2 sin (x) - cos (2 x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 sin (x)) - \frac{d}{d x} (cos (2 x))

\frac{d}{d x} (2 sin (x)) = 2 cos (x)

\frac{d}{d x} (cos (2 x)) = - sin (2 x) \cdot 2

= 2 cos (x) - (- sin (2 x) \cdot 2)

Simplify

= 2 cos (x) + 2 sin (2 x)

y^{^{''}} - 4 y^{^{'}} + 3 y = 10 e^{3 t}

\frac{d y}{d x} = \frac{sin ( x )}{cos ( y )}

\int_{0}^{\infty} (e^{- x}) d x

\int 11 x^{10} d x

x \to 1 lim (\frac{x ^{2}}{x ^{2} - 1})

What is the derivative of 2sin(x-cos(2x)) ?
The derivative of 2sin(x-cos(2x)) is 2cos(x)+2sin(2x)
What is the first derivative of 2sin(x-cos(2x)) ?
The first derivative of 2sin(x-cos(2x)) is 2cos(x)+2sin(2x)