What is the sum from n=0 to infinity of 5n ?

The sum from n=0 to infinity of 5n is diverges

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sum from n=0 to infinity of 5n

n = 0 \sum \infty 5 n

diverges

Solution steps

n = 0 \sum \infty 5 n

Apply the constant multiplication rule:

\sum c \cdot a_{n} = c \cdot \sum a_{n}

= 5 \cdot n = 0 \sum \infty n

Apply Series Divergence Test:

diverges

= 5 diverges

= diverges

\int \frac{( 7 ( 1 - tan ^{2} ( x ) ) )}{sec ^{2} ( x )} d x

\frac{\partial}{\partial x} (ln (4 x^{2} + 7 y^{2} + 4))

\int x^{2} I n (x) d x

f (x) = 2 e^{5 x}

x \to 3 lim (x^{2} - 3 x + 5)

What is the sum from n=0 to infinity of 5n ?
The sum from n=0 to infinity of 5n is diverges