What is the derivative of (x^2-1/(x-1)) ?

The derivative of (x^2-1/(x-1)) is 1

What is the first derivative of (x^2-1/(x-1)) ?

The first derivative of (x^2-1/(x-1)) is 1

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\frac{d}{d x} (\frac{x ^{2} - 1}{x - 1})

1

Solution steps

\frac{d}{d x} (\frac{x ^{2} - 1}{x - 1})

Simplify

\frac{x ^{2} - 1}{x - 1} : x + 1

= \frac{d}{d x} (x + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d x}{d x} + \frac{d}{d x} (1)

\frac{d x}{d x} = 1

\frac{d}{d x} (1) = 0

= 1 + 0

Simplify

= 1

x \to 4 lim (4)

y^{^{''}} - y^{^{'}} - 6 y = 0, y (0) = - 2, y^{^{'}} (0) = 4

\frac{\partial}{\partial x} (3 x y + e^{- x^{2} y})

\int \frac{x}{2 e ^{x}} d x

6 x^{4} (7 - 6 x)^{3}

What is the derivative of (x^2-1/(x-1)) ?
The derivative of (x^2-1/(x-1)) is 1
What is the first derivative of (x^2-1/(x-1)) ?
The first derivative of (x^2-1/(x-1)) is 1