What is the d/(da)(5a^9b^3+15a^6b^7) ?

The d/(da)(5a^9b^3+15a^6b^7) is 45b^3a^8+90b^7a^5

What is the first d/(da)(5a^9b^3+15a^6b^7) ?

The first d/(da)(5a^9b^3+15a^6b^7) is 45b^3a^8+90b^7a^5

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\frac{d}{d a} (5 a^{9} b^{3} + 15 a^{6} b^{7})

45 b^{3} a^{8} + 90 b^{7} a^{5}

Solution steps

\frac{d}{d a} (5 a^{9} b^{3} + 15 a^{6} b^{7})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d a} (5 a^{9} b^{3}) + \frac{d}{d a} (15 a^{6} b^{7})

\frac{d}{d a} (5 a^{9} b^{3}) = 45 b^{3} a^{8}

\frac{d}{d a} (15 a^{6} b^{7}) = 90 b^{7} a^{5}

= 45 b^{3} a^{8} + 90 b^{7} a^{5}

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\frac{d y}{d x} = 8 x^{7} - 2 sec^{2} (x)

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What is the d/(da)(5a^9b^3+15a^6b^7) ?
The d/(da)(5a^9b^3+15a^6b^7) is 45b^3a^8+90b^7a^5
What is the first d/(da)(5a^9b^3+15a^6b^7) ?
The first d/(da)(5a^9b^3+15a^6b^7) is 45b^3a^8+90b^7a^5