What is the integral from 1 to x of t^4 ?

The integral from 1 to x of t^4 is (x^5-1)/5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 1 to x of t^4

\int_{1}^{x} t^{4} d t

\frac{x ^{5} - 1}{5}

Solution steps

\int_{1}^{x} t^{4} d t

Apply the Power Rule

: [\frac{t ^{5}}{5}]_{1}^{x}

= [\frac{t ^{5}}{5}]_{1}^{x}

Compute the boundaries:

\frac{x ^{5}}{5} - \frac{1}{5}

= \frac{x ^{5}}{5} - \frac{1}{5}

Simplify

= \frac{x ^{5} - 1}{5}

f (x) = (x^{2} - 2)^{2}

\frac{d}{d x} (ln (3 x^{2} + 2 x))

x \to 0 + lim (csc (x) - cot (x))

n = 5 \sum \infty \frac{6}{n ^{2} - 1}

5^{x}

What is the integral from 1 to x of t^4 ?
The integral from 1 to x of t^4 is (x^5-1)/5