What is the integral from 1 to 2 of (3x^{-2}) ?

The integral from 1 to 2 of (3x^{-2}) is 3/2

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integral from 1 to 2 of (3x^{-2})

\int_{1}^{2} (3 x^{- 2}) d x

\frac{3}{2}

Decimal Notation

1.5

Solution steps

\int_{1}^{2} 3 x^{- 2} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 \cdot \int_{1}^{2} x^{- 2} d x

Apply the Power Rule

: [- \frac{1}{x}]_{1}^{2}

= 3 [- \frac{1}{x}]_{1}^{2}

Compute the boundaries:

\frac{1}{2}

= 3 \cdot \frac{1}{2}

Simplify

= \frac{3}{2}

\int 2 - 2 x^{2} d x

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What is the integral from 1 to 2 of (3x^{-2}) ?
The integral from 1 to 2 of (3x^{-2}) is 3/2