What is the tangent of f(x)=-3cos(x),\at x=(-pi)/3 ?

The tangent of f(x)=-3cos(x),\at x=(-pi)/3 is y=-(3sqrt(3))/2 x+(-3-sqrt(3)pi)/2

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tangent of f(x)=-3cos(x),\at x=(-pi)/3

tangent of

f (x) = - 3 cos (x), at x = \frac{- π}{3}

y = - \frac{3 3}{2} x + \frac{- 3 - 3 π}{2}

Solution steps

Find the tangent point:

(\frac{- π}{3}, - \frac{3}{2})

Find the slope of

f (x) = - 3 cos (x) : \frac{df ( x )}{d x} = 3 sin (x)

Compute the slope of

f (x) = - 3 cos (x)

x = \frac{- π}{3} : m = - \frac{3 3}{2}

Find the line with slope m=

- \frac{3 3}{2}

and passing through

(\frac{- π}{3}, - \frac{3}{2}) : y = - \frac{3 3}{2} x + \frac{- 3 - 3 π}{2}

y = - \frac{3 3}{2} x + \frac{- 3 - 3 π}{2}

x \to 0 lim ((1 - x)^{- \frac{1}{x}})

\frac{d}{d x} (ln (\frac{x ^{2} - 3 x + 2}{x ^{2} + 1}))

\frac{- 3 x ^{5} - x ^{4} - x ^{3} + 4 x ^{2}}{x ^{2}}

\int x (x^{3} - \frac{1}{x}) d x

x = 1, x = 6 - y^{2}

What is the tangent of f(x)=-3cos(x),\at x=(-pi)/3 ?
The tangent of f(x)=-3cos(x),\at x=(-pi)/3 is y=-(3sqrt(3))/2 x+(-3-sqrt(3)pi)/2