What is (\partial)/(\partial z)(9xsin(y-z)) ?

The answer to (\partial)/(\partial z)(9xsin(y-z)) is -9xcos(y-z)

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(\partial)/(\partial z)(9xsin(y-z))

\frac{\partial}{\partial z} (9 x sin (y - z))

- 9 x cos (y - z)

Solution steps

\frac{\partial}{\partial z} (9 x sin (y - z))

Treat

x, y

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 9 x \frac{\partial}{\partial z} (sin (y - z))

Apply the chain rule:

cos (y - z) \frac{\partial}{\partial z} (y - z)

= cos (y - z) \frac{\partial}{\partial z} (y - z)

\frac{\partial}{\partial z} (y - z) = - 1

= 9 x cos (y - z) (- 1)

Simplify

= - 9 x cos (y - z)

y^{^{''}} + y^{^{'}} - 3 y = 6 sin (2 x)

(sin^{2} (2 x))^{^{'}}

\frac{d}{d x} (ln (2 x^{2} + 4))

y^{^{'}} = (π x + y + π^{2})^{2}

\frac{1}{x - 1}, 13

What is (\partial)/(\partial z)(9xsin(y-z)) ?
The answer to (\partial)/(\partial z)(9xsin(y-z)) is -9xcos(y-z)