What is the integral from 1 to infinity of 6/(x^3) ?

The integral from 1 to infinity of 6/(x^3) is 3

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integral from 1 to infinity of 6/(x^3)

\int_{1}^{\infty} \frac{6}{x ^{3}} d x

3

Solution steps

\int_{1}^{\infty} \frac{6}{x ^{3}} d x

Compute the indefinite integral:

\int \frac{6}{x ^{3}} d x = - \frac{3}{x ^{2}} + C

Compute the boundaries:

\int_{1}^{\infty} \frac{6}{x ^{3}} d x = 0 - (- 3)

= 0 - (- 3)

Simplify

= 3

\frac{\partial}{\partial x} (1.2)

y^{^{'}} = 1 + x + y + x y

\int_{6}^{8} \frac{42}{( x - 6 ) ^{3}} d x

\int x^{2} e^{x^{3}} d x

(0.1) (3)

What is the integral from 1 to infinity of 6/(x^3) ?
The integral from 1 to infinity of 6/(x^3) is 3