What is the tangent of f(x)=2x^3-2x,(-1,0) ?

The tangent of f(x)=2x^3-2x,(-1,0) is y=4x+4

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tangent of f(x)=2x^3-2x,(-1,0)

tangent of

f (x) = 2 x^{3} - 2 x, (- 1, 0)

y = 4 x + 4

Solution steps

Find the slope of

f (x) = 2 x^{3} - 2 x : \frac{df ( x )}{d x} = 6 x^{2} - 2

Compute the slope of

f (x) = 2 x^{3} - 2 x

(- 1, 0) : m = 4

Find the line with slope m=

4

and passing through

(- 1, 0) : y = 4 x + 4

y = 4 x + 4

\int \frac{121}{x ^{3} - 11 x ^{2}} d x

f (x) = 7 x + 4

\frac{d}{d x} ((x y + 1)^{2})

x \to 2 lim (x^{2} - x + 2)

\int \frac{2 ^{l n (x)}}{x} d x

What is the tangent of f(x)=2x^3-2x,(-1,0) ?
The tangent of f(x)=2x^3-2x,(-1,0) is y=4x+4