What is the derivative of 2x^2+4x ?

The derivative of 2x^2+4x is 4x+4

What is the first derivative of 2x^2+4x ?

The first derivative of 2x^2+4x is 4x+4

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\frac{d}{d x} (2 x^{2} + 4 x)

4 x + 4

Solution steps

\frac{d}{d x} (2 x^{2} + 4 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{2}) + \frac{d}{d x} (4 x)

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d}{d x} (4 x) = 4

= 4 x + 4

1000 e^{- 0.02 p}

x \to 2 lim ([f (x) + g (x)])

\int 2 x^{2} cos (\frac{nπ x}{2}) d x

x ln (x)

x \to + 2 lim (\frac{( x ^{2} - 2 x )}{( x ^{2} - 4 x + 4 )})

What is the derivative of 2x^2+4x ?
The derivative of 2x^2+4x is 4x+4
What is the first derivative of 2x^2+4x ?
The first derivative of 2x^2+4x is 4x+4