What is the derivative of y=2sqrt(x) ?

The derivative of y=2sqrt(x) is 1/(sqrt(x))

What is the first derivative of y=2sqrt(x) ?

The first derivative of y=2sqrt(x) is 1/(sqrt(x))

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derivative of

y = 2 x

\frac{1}{x}

Solution steps

\frac{d}{d x} (2 x)

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (x)

Apply radical rule:

a = a^{\frac{1}{2}}

= 2 \frac{d}{d x} (x^{\frac{1}{2}})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 2 \cdot \frac{1}{2} x^{\frac{1}{2} - 1}

Simplify

2 \cdot \frac{1}{2} x^{\frac{1}{2} - 1} : \frac{1}{x}

= \frac{1}{x}

\frac{d}{d x} (\frac{2}{5} x^{3} cos (x))

\frac{d}{d x} (ln (x^{2} y))

\frac{d}{d x} (\frac{6 x ^{2} + 8 x + 8}{x})

\frac{d}{d x} (84 x^{6} + 12 x^{3} - 24 x^{2})

\int (1 - 2 x)^{4} d x

What is the derivative of y=2sqrt(x) ?
The derivative of y=2sqrt(x) is 1/(sqrt(x))
What is the first derivative of y=2sqrt(x) ?
The first derivative of y=2sqrt(x) is 1/(sqrt(x))