What is laplacetransform 5sin(3t) ?

The answer to laplacetransform 5sin(3t) is (15)/(s^2+9)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

laplacetransform 5sin(3t)

laplace transform

5 sin (3 t)

\frac{15}{s ^{2} + 9}

Solution steps

L {5 sin (3 t)}

Use the constant multiplication property of Laplace Transform:

For function

f (t)

and constant

a : L {a \cdot f (t)} = a \cdot L {f (t)}

= 5 L {sin (3 t)}

L {sin (3 t)} : \frac{3}{s ^{2} + 9}

= 5 \cdot \frac{3}{s ^{2} + 9}

Refine

5 \frac{3}{s ^{2} + 9} : \frac{15}{s ^{2} + 9}

= \frac{15}{s ^{2} + 9}

e^{x^{6}}

\int \frac{4 + x + x}{x} d x

\frac{\partial}{\partial y} (2 x y^{2} + y)

f (x) = (\frac{x}{x ^{2} + 1})^{2}

\frac{d y}{d x} + y = x e^{- x} + 1

What is laplacetransform 5sin(3t) ?
The answer to laplacetransform 5sin(3t) is (15)/(s^2+9)