What is the integral of-(2ln(x))/(x^2) ?

The integral of-(2ln(x))/(x^2) is -2(-(ln(x))/x-1/x)+C

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integral of-(2ln(x))/(x^2)

\int - \frac{2 ln ( x )}{x ^{2}} d x

- 2 (- \frac{ln ( x )}{x} - \frac{1}{x}) + C

Solution steps

\int - \frac{2 ln ( x )}{x ^{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - 2 \cdot \int \frac{ln ( x )}{x ^{2}} d x

Apply Integration By Parts

: - \frac{ln ( x )}{x} - \int - \frac{1}{x ^{2}} d x

= - 2 (- \frac{ln ( x )}{x} - \int - \frac{1}{x ^{2}} d x)

\int - \frac{1}{x ^{2}} d x = \frac{1}{x}

= - 2 (- \frac{ln ( x )}{x} - \frac{1}{x})

Add a constant to the solution

= - 2 (- \frac{ln ( x )}{x} - \frac{1}{x}) + C

\frac{d}{d x} (ln (\frac{x ^{2}}{( x - 4 )}))

\frac{d}{d x} (x^{3} e^{x^{2}})

f (x) = (3 x - 2)^{4}

\int cos (2 x) - 1 d x

\frac{d y}{d x} = \frac{( x - y )}{( x + 2 y )}

What is the integral of-(2ln(x))/(x^2) ?
The integral of-(2ln(x))/(x^2) is -2(-(ln(x))/x-1/x)+C