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Popular >

y^'=9x+y,y(0)=4

Solution

y^{^{'}} = 9 x + y, y (0) = 4

Solution

y = - 9 (x + 1) + 13 e^{x}

Solution steps

y^{'} (x) = 9 x + y

Solve linear ODE:

y = - 9 (x + 1) + 13 e^{x}

y = - 9 (x + 1) + 13 e^{x}

Popular Examples

integral from 0 to 1 of (13)/(4y-1)

\int_{0}^{1} \frac{13}{4 y - 1} d y

derivative of \sqrt[3]{x^4+5x}derivative of

derivative of e^{-8x}derivative of

e^{- 8 x}

sum from n=0 to infinity of e^n

n = 0 \sum \infty e^{n}

(4 x)^{^{'}}

Frequently Asked Questions (FAQ)

What is the solution for y^'=9x+y,y(0)=4 ?
The solution for y^'=9x+y,y(0)=4 is y=-9(x+1)+13e^x