What is laplacetransform 1e^{4t} ?

The answer to laplacetransform 1e^{4t} is 1/(s-4)

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laplacetransform 1e^{4t}

laplace transform

1 e^{4 t}

\frac{1}{s - 4}

Solution steps

L {1 \cdot e^{4 t}}

Use the constant multiplication property of Laplace Transform:

For function

f (t)

and constant

a : L {a \cdot f (t)} = a \cdot L {f (t)}

= 1 L {e^{4 t}}

L {e^{4 t}} : \frac{1}{s - 4}

= 1 \cdot \frac{1}{s - 4}

Refine

1 \frac{1}{s - 4} : \frac{1}{s - 4}

= \frac{1}{s - 4}

\int \frac{x ^{2}}{( x ^{3} + 2 ) ^{2}} d x

\frac{6 x}{x + 7}, at x = 1

\frac{\partial}{\partial y} (x e^{\frac{y}{x}})

x^{2} - 2

\int \frac{y ^{2} + 6 y + 9}{( y ^{2} + 9 ) ^{2}} d y

What is laplacetransform 1e^{4t} ?
The answer to laplacetransform 1e^{4t} is 1/(s-4)