What is the derivative of g(x)=(1+2x)/(3-4x) ?

The derivative of g(x)=(1+2x)/(3-4x) is (10)/((3-4x)^2)

What is the first derivative of g(x)=(1+2x)/(3-4x) ?

The first derivative of g(x)=(1+2x)/(3-4x) is (10)/((3-4x)^2)

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derivative of

g (x) = \frac{1 + 2 x}{3 - 4 x}

\frac{10}{( 3 - 4 x ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{1 + 2 x}{3 - 4 x})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( 1 + 2 x ) ( 3 - 4 x ) - \frac{d}{d x} ( 3 - 4 x ) ( 1 + 2 x )}{( 3 - 4 x ) ^{2}}

\frac{d}{d x} (1 + 2 x) = 2

\frac{d}{d x} (3 - 4 x) = - 4

= \frac{2 ( 3 - 4 x ) - ( - 4 ) ( 1 + 2 x )}{( 3 - 4 x ) ^{2}}

Simplify

\frac{2 ( 3 - 4 x ) - ( - 4 ) ( 1 + 2 x )}{( 3 - 4 x ) ^{2}} : \frac{10}{( 3 - 4 x ) ^{2}}

= \frac{10}{( 3 - 4 x ) ^{2}}

\int x (4 x + 5)^{3} d x

\frac{d y}{d x}, x y = 28

(- 1.2) (- 2.3)

\int sin^{4} (y) cos (y) d y

What is the derivative of g(x)=(1+2x)/(3-4x) ?
The derivative of g(x)=(1+2x)/(3-4x) is (10)/((3-4x)^2)
What is the first derivative of g(x)=(1+2x)/(3-4x) ?
The first derivative of g(x)=(1+2x)/(3-4x) is (10)/((3-4x)^2)