What is the integral of sin(x)cox ?

The integral of sin(x)cox is co(-xcos(x)+sin(x))+C

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integral of sin(x)cox

\int sin (x) co x d x

co (- x cos (x) + sin (x)) + C

Solution steps

\int sin (x) co x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= co \cdot \int sin (x) x d x

Apply Integration By Parts

: - x cos (x) - \int - cos (x) d x

= co (- x cos (x) - \int - cos (x) d x)

\int - cos (x) d x = - sin (x)

= co (- x cos (x) - (- sin (x)))

Simplify

= co (- x cos (x) + sin (x))

Add a constant to the solution

= co (- x cos (x) + sin (x)) + C

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\frac{d}{d x} (a csc^{2} (k x))

\frac{d}{d x} ((6 x + 5) (x^{3} - 2))

x^{3} - 2 x^{2} + 2, 3 x^{2} + 3 x - 13

What is the integral of sin(x)cox ?
The integral of sin(x)cox is co(-xcos(x)+sin(x))+C