What is the limit as x approaches-1/2 of 7/(2x+1) ?

The limit as x approaches-1/2 of 7/(2x+1) is diverges

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limit as x approaches-1/2 of 7/(2x+1)

x \to - \frac{1}{2} lim (\frac{7}{2 x + 1})

diverges

Solution steps

x \to - \frac{1}{2} lim (\frac{7}{2 x + 1})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to - \frac{1}{2} + lim (\frac{7}{2 x + 1}) = \infty

x \to - \frac{1}{2} - lim (\frac{7}{2 x + 1}) = - \infty

= diverges

- x^{2} + 2 x, 3 x^{3} - x^{2} - 10 x

5 sin (- 3 x + \frac{π}{4})

x \to 3 lim (5^{2} - 9 x + 7)

\int_{- 2}^{3} x^{2} - 3 d x

e^{5 t} t^{3}

What is the limit as x approaches-1/2 of 7/(2x+1) ?
The limit as x approaches-1/2 of 7/(2x+1) is diverges