What is the derivative of 1+2e^{3x} ?

The derivative of 1+2e^{3x} is 6e^{3x}

What is the first derivative of 1+2e^{3x} ?

The first derivative of 1+2e^{3x} is 6e^{3x}

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\frac{d}{d x} (1 + 2 e^{3 x})

6 e^{3 x}

Solution steps

\frac{d}{d x} (1 + 2 e^{3 x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (1) + \frac{d}{d x} (2 e^{3 x})

\frac{d}{d x} (1) = 0

\frac{d}{d x} (2 e^{3 x}) = 6 e^{3 x}

= 0 + 6 e^{3 x}

Simplify

= 6 e^{3 x}

f (y) = 2 x, 0, 4

e^{t} cos (t) + e^{t} sin (t)

\frac{d}{d x} (arctan (sin (2 x)))

\int 1 - 4 (\frac{1}{2} sin (x))^{2} d x

ln (1 - 5 x)

What is the derivative of 1+2e^{3x} ?
The derivative of 1+2e^{3x} is 6e^{3x}
What is the first derivative of 1+2e^{3x} ?
The first derivative of 1+2e^{3x} is 6e^{3x}