What is area y=2x+2,y=x^2-2 ?

The answer to area y=2x+2,y=x^2-2 is -(16sqrt(5))/3+12sqrt(5)

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area y=2x+2,y=x^2-2

area

y = 2 x + 2, y = x^{2} - 2

- \frac{16 5}{3} + 125

Decimal Notation

14.90711 \dots

Solution steps

Apply the area formula:

\int_{1 - 5}^{1 + 5} 2 x + 2 - (x^{2} - 2) d x

Solve

\int_{1 - 5}^{1 + 5} 2 x + 2 - (x^{2} - 2) d x : - \frac{16 5}{3} + 125

The area is:

= - \frac{16 5}{3} + 125

y^{2} = 2 x, y = - 4 + x

\int \frac{1}{25 - 4 x ^{2}} d x

\int t \cdot cos (t) d t

\int 18 sin^{3} (x) cos^{2} (x) d x

y^{^{''}} + 4 y^{^{'}} + 5 y = - 10 x + e^{- x}

What is area y=2x+2,y=x^2-2 ?
The answer to area y=2x+2,y=x^2-2 is -(16sqrt(5))/3+12sqrt(5)