What is the derivative of (8x-1^2) ?

The derivative of (8x-1^2) is 16(8x-1)

What is the first derivative of (8x-1^2) ?

The first derivative of (8x-1^2) is 16(8x-1)

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\frac{d}{d x} ((8 x - 1)^{2})

16 (8 x - 1)

Solution steps

\frac{d}{d x} ((8 x - 1)^{2})

Apply the chain rule:

2 (8 x - 1) \frac{d}{d x} (8 x - 1)

= 2 (8 x - 1) \frac{d}{d x} (8 x - 1)

\frac{d}{d x} (8 x - 1) = 8

= 2 (8 x - 1) \cdot 8

Simplify

= 16 (8 x - 1)

\int 7^{c o s (x)} sin (x) d x

y = x cos (x)

x = 63 - 7 y^{2}, x = 7 y^{2} - 63

t^{3} - t

\frac{d}{d x} (1 - x^{2} - x arccos (x))

What is the derivative of (8x-1^2) ?
The derivative of (8x-1^2) is 16(8x-1)
What is the first derivative of (8x-1^2) ?
The first derivative of (8x-1^2) is 16(8x-1)