What is the limit as x approaches-3 of-(1/(x^2-9)) ?

The limit as x approaches-3 of-(1/(x^2-9)) is diverges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches-3 of-(1/(x^2-9))

x \to - 3 lim (- (\frac{1}{x ^{2} - 9}))

diverges

Solution steps

x \to - 3 lim (- \frac{1}{x ^{2} - 9})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to - 3 + lim (- \frac{1}{x ^{2} - 9}) = \infty

x \to - 3 - lim (- \frac{1}{x ^{2} - 9}) = - \infty

= diverges

\int \frac{3 x ^{3} + 6 x ^{2} + 3}{3 x + 3} d x

x \to \infty lim (0.6 6^{x})

\int \frac{1}{( a ^{2} + x ^{2} ) ^{2}} d x

\frac{\partial}{\partial x} (\frac{1}{x ^{2} + y})

What is the limit as x approaches-3 of-(1/(x^2-9)) ?
The limit as x approaches-3 of-(1/(x^2-9)) is diverges