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Popular >

y^{''}+4y^'+4=0

Solution

y^{^{''}} + 4 y^{^{'}} + 4 = 0

Solution

y = c_{1} + c_{2} e^{- 4 t} - t

Solution steps

y^{''} (t) + 4 y^{'} (t) + 4 = 0

Solve linear ODE:

y = c_{1} + c_{2} e^{- 4 t} - t

y = c_{1} + c_{2} e^{- 4 t} - t

Popular Examples

integral of cos^9(x)tan^8(x)

\int cos^{9} (x) tan^{8} (x) d x

(\partial)/(\partial x)(3e^x)

\frac{\partial}{\partial x} (3 e^{x})

derivative of f(2)=11x^2+5x derivative of

f (2) = 11 x^{2} + 5 x

tangent of f(x)=x^2-x^4,(1,0)tangent of

f (x) = x^{2} - x^{4}, (1, 0)

derivative of ((x+2/x)^3+((x-2)/x)^3)

\frac{d}{d x} ((\frac{x + 2}{x})^{3} + (\frac{x - 2}{x})^{3})

Frequently Asked Questions (FAQ)

What is the solution for y^{''}+4y^'+4=0 ?
The solution for y^{''}+4y^'+4=0 is y=c_{1}+c_{2}e^{-4t}-t